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For the hyperbola `x^2/ cos^2 alpha - y^2 /sin^2 alpha = 1;(0 lt alphalt pi/4)`A. EccentricityB. Abscissa of fociC. DirectrixD. Vertex |
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Answer» Correct Answer - B `e^(2)=1+(b^(2))/(a^(2))=1+(sin^(2)alpha)/(cos^(2)alpha)=(1)/(cos^(2)alpha)` `a^(2)=cos^(2)alpha` `therefore" "a^(2)e^(2)=1` Hence, the foci are `(pmae, 0)-=(pm1,0)`, which are independent of `alpha.` |
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