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For the ideal RL circuit shown, the resistance is `R=10.0Omega`, the inductance is `L=5.0 H` and the battery has voltage `xi_("bat") = 12` volts. Some time after the switch S in the circuit is closed, the ammeter in the circuit reads `0.40A`. If the rate at which energy is being stored by the inductor at this instant is `(16)/(x)` Watts, what is the value of x? A. 3B. 4C. 5D. None of these |
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Answer» Correct Answer - C `(dU)/(dt)=(Lidi)/(dt)=i(V_(L))=i(V-V_(R))=0.4(12-0.4xx10)=3.2"Watts"=(16)/(5)"watts"impliesx=5` |
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