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For the ion `BrF_(5)` the only correct combination isA. `[NiCl_(4)]^(2-)` - squar-planar , `[Ni(CN)_(4)]^(2-)` -paramagneticB. `[NiCl_(4)]^(2-)` diamagnetic, `[Ni(CO)_(4)]`- square-planarC. `[Ni(CN)_(4)]^(2-)`-tetrahedral , `[Ni(CO)_(4)]`- paramagneticD. `[NiCl_(4)]^(2-)` - paramagnetic , `[Ni(CO)_(4)]` - tetrahedral |
Answer» Correct Answer - D | |