For the molecule CH3CH(OH) CH(OH)CH(OH) CH3 total number of stereoisom

1.	For the molecule CH3CH(OH) CH(OH)CH(OH) CH3 total number of stereoisomers and meso form respectively are?pls explain with structures
Answer» Answer:Trihydroxyglutaric Explanation: Trihydroxyglutaric acid (HO2C-CHOH-CHOH-CHOH-CO2H) exists in four stereoisomeric forms, two of which are OPTICALLY acitve while the other are meso-forms. REASON: It contains two asymmeric and one pseudo-asymmeric CARBON atom.

For the molecule CH3CH(OH) CH(OH)CH(OH) CH3 total number of stereoisomers and meso form respectively are?pls explain with structures

Answer»

Answer:Trihydroxyglutaric

Explanation:

Trihydroxyglutaric acid (HO2C-CHOH-CHOH-CHOH-CO2H) exists in four stereoisomeric forms, two of which are OPTICALLY acitve while the other are meso-forms. REASON: It contains two asymmeric and one pseudo-asymmeric CARBON atom.

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For the molecule CH3CH(OH) CH(OH)CH(OH) CH3 total number of stereoisomers and meso form respectively are?pls explain with structures

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