For the pair of linear equations a1x + b1y + c1=0 and a2x + b2y + c2=0

1.	For the pair of linear equations a1x + b1y + c1=0 and a2x + b2y + c2=0, the solution set are x=(b1c2−b2c1)(a1b2−a2b1) and y=(c1a2−c2a1)(a1b2−a2b1). They can also be written as:
Answer» For the pair of linear equations $a_{1} x$ + $b_{1} y$ + $c_{1} = 0$ and $a_{2} x$ + $b_{2} y$ + $c_{2} = 0$ , the solution set are $x = \frac{(b_{1} c_{2} - b_{2} c_{1})}{(a_{1} b_{2} - a_{2} b_{1})}$ and $y = \frac{(c_{1} a_{2} - c_{2} a_{1})}{(a_{1} b_{2} - a_{2} b_{1})}$ . They can also be written as:

For the pair of linear equations a1x + b1y + c1=0 and a2x + b2y + c2=0, the solution set are x=(b1c2−b2c1)(a1b2−a2b1) and y=(c1a2−c2a1)(a1b2−a2b1). They can also be written as:

Answer»

For the pair of linear equations $a_{1} x$ + $b_{1} y$ + $c_{1} = 0$ and $a_{2} x$ + $b_{2} y$ + $c_{2} = 0$ , the solution set are $x = \frac{(b_{1} c_{2} - b_{2} c_{1})}{(a_{1} b_{2} - a_{2} b_{1})}$ and $y = \frac{(c_{1} a_{2} - c_{2} a_{1})}{(a_{1} b_{2} - a_{2} b_{1})}$ . They can also be written as:

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For the pair of linear equations a1x + b1y + c1=0 and a2x + b2y + c2=0, the solution set are x=(b1c2−b2c1)(a1b2−a2b1) and y=(c1a2−c2a1)(a1b2−a2b1). They can also be written as:

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