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For the process `H_(2)O(l)` (1 bar, 373 K) `rarr H_(2)O` (1 bar, 373 K), the correct set of thermodynamic parameters isA. `DeltaG=0, DeltaS=+ve`B. `DeltaG=0, DeltaS=-ve`C. `DeltaG=+ve, DeltaS=0`D. `DeltaG=-ve, DeltaS=+ve` |
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Answer» Correct Answer - A Since, liquid is passing in to gaseous phase so entropy will increase and at 373 K the phase transformation remains at equilibrium. So `DeltaG=0`. |
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