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For the reaction 2 HI (g) hArr H_(2) (g) + I_(2) (g)at 720 K , the equilibrium constant value is 50 . The equilibrium constant for the reaction H_(2) (g) + I_(2) (g) hArr 2 HI (g) at the same temperature will be ……….. |
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Answer» Solution :`0.02` Forward reaction EQUILIBRIUM constant `K_1= 50` Reverse reaction equilibrium constant `K_(2) = ?` `K_(2) = (1)/(K_(1)) = (1)/(50) = 0.02` |
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