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For the reaction : `2 NH_(3) (g) rarr N_(2) (g) + 3H_(2) (g)`. What is the % of `NH_(3)` converted if the mixture diffuses twice as fast as that `SO_(2)` under similar conditions.A. 3.125B. 6.25C. 12.5D. None of these |
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Answer» Correct Answer - B `{:(,2NH_(3) (g),rarr,N_(2) (g),+,3H_(2) (g),),("Initially",1,,,,,),("After",1 - 2x,,x,,3x,):}` decomposition `(r_("mix"))/(r_(SO_(2))) = 2 = sqrt((M_(SO_(2)))/(M_("Mix")))` `M_("mix") = (64)/(4) = 16 = M_("avg")` `M_(avg) = (1 xx 17)/(1 + 2x) = 16` `17 = 16 + 32 x` 1 = 32 x `x = (1)/(32)` `% NH_(3) = (2x)/(1) xx 100` `= (1)/(16) xx 100 = 6.25 %` |
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