For the reaction 2 NO_(2) (g) hArr 2NO (g) + O_(2) (g) , K_(C) = 1.8 xx 10^(-6) at 185^(@) C . At the same temperature the value of K_(C) for the reaction . NO (g) + (1)/(2) O_(2) hArr NO_(2) (g) is ……………

For the reaction 2 NO_(2) (g) hArr 2NO (g) + O_(2) (g) , K_(C) = 1.8 x

1.	For the reaction 2 NO_(2) (g) hArr 2NO (g) + O_(2) (g) , K_(C) = 1.8 xx 10^(-6) at 185^(@) C . At the same temperature the value of K_(C) for the reaction . NO (g) + (1)/(2) O_(2) hArr NO_(2) (g) is ……………
Answer» `0.9 XX 10^(6)` `7.5 xx 10^(2)` `1.95 xx 10^(-3)` `1.95 xx 10^(3)` Solution :The reaction is REVERSED and halved. `K_(C) = (1)/(sqrt(1.8 xx 10^(-6)) = 7.5 xx 10^(2)`