1.

For the reaction , 2 NO (g) + Cl_(2) (g) hArr 2 NOCl (g) " if partial pressure " p_(NOCl)= 0*32 " atm, " p_(No) = 0*22 " atm" and p_(Cl_(2))= 0*11 " atm, then find "K_(p).

Answer»


Solution :`K_(p) = p_(NOCI)^(2)/ (p_(NO)^(2) xx p_(Cl_(2)))= (0*32 " atm")^(2)/(0*22 " atm"^(2)xx 0*11 "atm")=19*23 " atm"^(-1)`


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