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For the reaction, 2Co +O_(2)rarr 2CO_(2), DeltaH = - 560 kJ . Two moles of CO andone mole ofO_(2) are takenin a container of volume 1 L. They completely reacts to form two moles of CO_(2). The gases deviate appreciably from ideal behaviour. Ifthe pressure in the vessel changesfrom 70 to 40 atm,find the magnitude ( absolute value)of DeltaU at 500 K ( 1 L atm = 0.1 kJ ). |
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Answer» Solution :`H =U +PV` `DELTAH+ DeltaU + Delta(PV) ` or ` DeltaH = DeltaU + VDeltaP` or `DeltaU = DeltaH -VDeltaP = - 560kJ - 1L( 40 atm-70 atm)` `=- 560 KJ + 30 Latm = - 560 kJ + 3-0 XX 0.1kJ = - 557 kJ ` Absolute value `=557 kJ . ` |
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