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For the reaction 2H(g)rarr H_(2)(g), the sign of DeltaH and DeltaS respectively are : |
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Answer» Solution :(i) The given reaction, `2H_((g))rarrH_(2(g))` is the FORMATION of `H_(2(g))` from FREE atoms. (ii) In the bond formation, energy is released equal and opposite to bond enthalpy of `H_(2) ` i.e., `-DeltaH_(H-H)^(@)` . Hence the reaction is exothermic and `DeltaAH` is negative. (iii) Since two H atoms FORM one `H_(2)` molecule, `Deltan=1-2=-1` and disorder is DECREASED. Hence ENTROPY change `Delta S lt O`. |
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