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For the reaction `2N_(2)O_(5)(g) to 4NO_(2) (g) + O_(2)(g)` , the rate of formation of `NO_(2)(g) ` is `2.8 xx 10^(-3) Ms^(-1)` . Calculate the rate of disapperance of `N_(2)O_(5)(g)`. |
Answer» `2N_(2)O_(5)(g) to 4NO_(2)(g) + O_(2)(g)` Rate of formation `(R_(f)) = (Delta[NO_(2)])/(Deltat) = 2.8 xx 10^(-3) ` M/s Rate of disapperance of `N_(2)O_(5)(g) = (Delta[N_(2)O_(5)])/(Deltat) = ?` Rate of reaction = `(1)/(2) (Delta[N_(2)O_(5)])/(Deltat) = (1)/(4) (Delta[NO_(2)])/(Deltat)` `(Delta[N_(2)O_(5)])/(Deltat) = (2)/(4) xx (Delta[NO_(2)])/(Deltat) = (1)/(2) xx 2.8 xx 10^(-3)` M/s `(Delta[N_(2)O_(5)])/(Deltat) = 1.4 xx 10^(-3) ` M/s |
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