For the reaction, 2NOCl(g)hArr2NO(g)+Cl_(2)(g) the value of K_(c)=3.75xx10^(-6) at 1069K. Calculate K_(p).

For the reaction, 2NOCl(g)hArr2NO(g)+Cl_(2)(g) the value of K_(c)=3.75

1.	For the reaction, 2NOCl(g)hArr2NO(g)+Cl_(2)(g) the value of K_(c)=3.75xx10^(-6) at 1069K. Calculate K_(p).
Answer» Solution :Since unit is not mentioned, it is to be assumed that the concentration is EXPRESSED in mol `L^(-)`. HENCE, R = 0.0831 L BAR `K^(-1)mol^(-1).DELTAN` for the REACTION is 3 - 2 = 1. `K_(p)=K_(c)(RT)^(Deltan)` becomes `K_(p)=K_(c)RT` `K_(p)=(3.75xx10^(-6))0.0831xx1069=3.33xx10^(-4)`.