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For the reaction, `2SO_(2(g))+O_(2(g))hArr2SO_(3(g))` What is `K_(c)` when the equilibrium concentration of `[SO_(2)]=0.60M,[O_(2)]=0.82Mand[SO_(3)]=1.90M` ?A. `12.229Lmol^(-1)`B. `24.5Lmol^(-1)`C. `36.0Lmol^(-1)`D. `2.67xx10^(3)Lmol^(-1)` |
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Answer» Correct Answer - A `K_(c)=([SO_(3)]^(2))/([SO_(2)]^(2)[O_(2)])=((1.9)^(2))/((0.6)^(2)(0.82))=12.229" L mol"^(-1)` |
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