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For the reaction, `A+B hArr 2C, 2` mol of `A` and `3` mol of `B` are allowed to react. If the equilibrium constant is `4` at `400^(@)C`, what will be the moles of `C` at equilibrium? |
Answer» `{:(,A,+,B,hArr,2C),("Initial moles",2,,3,,0),("moles at equilibrium",(2-x),,(3-x),,2x):}` `:. K_(c )=([C]^(2))/([A][B])=(4x^(2).V.V)/(V^(2)(2-x)(3-x))` `4=(4x^(2))/((2-x)(3-x))` `:. x^(2)=6-5x+x^(2)` `({:([C]=(2x)/V),([A]=(2-x)/V),([B]=(3-x)/V):})` `:. x=1.2` moles of `C` at equilibrium `=2x=2xx1.2=2.4` |
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