1.

For the reaction A+BhArrC+D, the equilibrium constant is 0.05 at 300K. Calculate the equilibrium constant for C+DhArrA+B at the same temperature.

Answer»

SOLUTION :`A+BhArrC+D""K=([C][D])/([A][B])` at EQUILIBRIUM
For `C+DhArrA+B,""K'=([A][B])/([C][D])` at equilibrium
`thereforeK'=1/K=1/0.05=20`.


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