For the reaction A rarr B,DeltaH = + 24kJ //mole For the reaction B rarrC , DeltaH= -18 kJ // mole . The decreasing order of enthalpy of A,B,C follows the order :

For the reaction A rarr B,DeltaH = + 24kJ //mole For the reaction B ra

1.	For the reaction A rarr B,DeltaH = + 24kJ //mole For the reaction B rarrC , DeltaH= -18 kJ // mole . The decreasing order of enthalpy of A,B,C follows the order :
Answer» A,B,C B,C,A C,B,A C,A,B Solution :`A rarr B, Delta H = +ve` means that `H (A)lt H(B)` `B rarr C, DeltaH = -ve` means that`H(B) gt H(C )` or `H(C ) lt H(B)` Addingthe given equations,we get `A rarrC, DeltaH = + 6 kJ mol^(-1)`. This means that `H(A)lt H(C )` COMBINING the above results. `H(A) lt H (C ) lt H(B)` or `H( B) gt H( C) gt H(A)` . Hence, decreasing ORDER of ENTHALPY is B,C,A.