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For the reaction AB_(2(g)) hArr AB_((g)) + B_((g)) if alpha is negligiable w.rt 1 then degree of dissociation (alpha) of AB_(2) is proportional to |
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Answer» `1/p` Total moles = `1+alpha` `K_(P)=(Palpha^(2))/(1-alpha^(2)), alpha LT lt IMPLIES K_(P)=P alpha^(2) implies alpha(1)/(sqrt(P))` & `P alpha(1)/(V)` |
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