1.

For the reaction Ag_(2)O(s)rarr 2Ag(s) + (1)/(2) O_(2)(g) , DeltaHis 30.56kJ mol^(-1) and Delta Sis 66JK^(-1) mol^(-1) at one atmosphere pressure. Calculate the temperature at which Delta G for it will be zero. What will be the direction of the reaction at this temperatureand at temperature above or below this temperature and why ?

Answer»


Solution :When `DeltaG = 0, T = (DELTAH )/(DeltaS) = ( 30560J mol^(-1))/( 66JK^(-1)mol^(-1))= 463.0K`
`DeltaG = DELTA H - T DeltaS `. Above 463K `, DeltaG = -ve` ( because `DeltaH ` and `Delta S` both are `+ve`) . Below 463K, `DeltaG = + ve`.


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