1.

For the reaction at 298 K 2 A+ B C, ◇H=400 kJ mol and ◇S=0.25 kJ K-1 mol-1 At what temperature will the reaction become spontaneous considering ◇H and ◇S to be constant over the temperature range​

Answer»

2000 KExplanation:Given reaction as : 2 A + B ⇒  C = > Δ H = 400 kJ mol⁻¹ and Δ S = 0.2 kJ K⁻¹ mol⁻¹ LET is first calculate TEMPERATURE at which the reaction will be in equilibrium.i.e. Δ G = 0We know : Δ G = Δ H - T Δ S= > Δ H - T Δ S = 0= > T = Δ H / Δ SPutting given VALUES here we get : = > T = 400 / 0.2 K= > T = 2000 KTherefore , the required temperature is 2000 K .



Discussion

No Comment Found