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For the reaction C(s) + CO_(2) (g) to 2 CO (g) K_(p) = 63 " atm at " 100 K . If at equilibriump_(CO) = 10_(p_(CO_(2)) , then the toal pressure of the gases at equilibrium is |
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Answer» `6*3` atm `K_(p)=(p^(2) CO)/p_(CO_(2)) or 63 = ((10p_(CO_(2))))/(p_(CO_(2)))` or `p_(CO_(2)) = 63/100 = 0.63 " atm"` ` p_(CO)= 10p_(CO_(2))= 10 xx 0.63 " atm " =6.3 " atm"` ` :. p_("TOTAL")= p_(CO_(2)) + p_(CO) = 0.63 + 6.3 = 6.93 " atm"` |
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