InterviewSolution
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InterviewSolution
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For the reaction `Cu(s)+2Ag^(o+)(aq)rarr Cu^(2+)(aq)+2Ag(s)` Fill in the blanks in the following table for the three solution at equilibrium. `{:("Solution",[Cu^(2+)(aq)],[Ag^(o+)(aq)],K L^(-1)),(,mol L^(-1),mol L^(-1),mol L^(-1)),(1.,(a),1.0xx10^(-9),2.0xx10^(15)),(2.,2.0xx10^(-7),1.0xx10^(-11),(b)),(3.,2.0xx10^(-2),(c),2.0xx10^(15)):}` |
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Answer» Correct Answer - A::B::C a. `K=([Cu^(2+)])/([Ag^(o+)]^(2))` `2.0xx10^(15)=([Cu^(2+)])/((1.0xx10^(-9))^(2))` `[Cu^(2+)]=2.0xx10^(15)xx(1.0xx10^(-9))^(2)=2.0xx10^(-3)` `:. a=2.0xx10^(-3) "mol" L^(-1)` b. `K=([Cu^(2+)])/([Ag^(o+)]^(2)) =(2.0xx10^(-7))/((1.0xx10^(-11))^(2))=2.0xx10^(15)` `b=2.0xx10^(15) "mol" L^(-1)` c. `K=([Cu^(2+)])/([Ag^(o+)]^(2))` `2.0xx10^(15)=(2.0xx10^(-2))/([Ag^(o+)]^(2))` ltbr or `[Ag^(o+)]=([2.0xx10^(-2)])/([2.0xx10^(15)])=3.16xx10^(-9)` |
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