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For the reaction`H_(2)(g)+(1)/(2)O_(2)(g)rarrH_(2)O(l),DeltaH=-285.8 kJ mol^(-1)` `DeltaS=-0.163 kJ mol^(-1) K^(-1)`. What is the value of free energy change at `27^(@)C` for the reactionA. `-236.9 kJ mol^(-1)`B. `-281.4 kJ mol^(-1)`C. `-334.7 kJ mol^(-1)`D. `+334.7 kJ mol^(-1)` |
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Answer» Correct Answer - A `DeltaG=DeltaH-TDeltaS, T=27+273=300 K` `DeltaG=(-285.8)-(300)(-0.163)=-236.9 kJ mol^(-1)` |
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