For the reaction H_(2) + I_(2) hArr 2 HI, " if intially 25 mL of "H_(2) and 20 " mL of "I_(2) are present ia a container in a container and at equilibrium, 30 mL of HI is foprmed , then calculate equilibrium constant.

For the reaction H_(2) + I_(2) hArr 2 HI, " if intially 25 mL of "H_(2

1.	For the reaction H_(2) + I_(2) hArr 2 HI, " if intially 25 mL of "H_(2) and 20 " mL of "I_(2) are present ia a container in a container and at equilibrium, 30 mL of HI is foprmed , then calculate equilibrium constant.
Answer» SOLUTION :`{:(,H_(2),+,I_(2),hArr,2 HI),(" Initial:",25 mL,,29 mL,,0),(" At EQM. :",25-x,,20-x,,2 x):}` ` :. " At equilibrium ",H_(2) = 25 - 15 10" mL," I_(2) = 20-15 " mL" and HI = 30 " mL".` As equal volumes contain equal number of mole , THEREFORE, volumes can be used in place of moles. HENCE, `K= [HI]^(2)/([H_(2)][I_(2)])=(30)^(2)/((10)(5))=900/50= 18`