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For the reaction H_2+I_2 hArr 2HI, DeltaH=12.40 Kcal the heat of formation of HI is _____ |
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Answer» Solution :`H_2+ I_2 to 2HI "" DeltaH`=12.40 K.cal `1//2 H_2 +1//2 I_2 to HI =DeltaH//2` `THEREFORE 12.40/2=6.20 "K.cal mol"^(-1)` |
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