InterviewSolution
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InterviewSolution
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For the reaction, `I^(-)+CIO_(3)^(-)+H_(2)SO_(4)rarrCI^(-)+HSO_(4)^(-)+I_(2)` the correct statement (s) in the balanced equation `is//are`A. stoichiometric coeffiecient of `HSO_(4)^(-)` is 6B. iodide is oxidisedC. suphur is reducedD. `H_(2)O` is one of the products |
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Answer» Correct Answer - A::B::D The oxidation half reaction is: `2I^(-)rarrI_(2)+2e^(-)` The reduction half rection is : `6H^(+)+CIO_(3)^(-)+6E^(-)rarrCI^(-)+3H_(2)O` Multiply eqn.(i) by 3 and add to eqn.(i) `6H^(+)+CIO_(3)^(-)+6e^(-)rarrCI^(-)+3H_(2)O` `6I^(-)rarr3I_(2)+6e^(-)` `(6I^(-)+6H^(+)+CIO_(3)^(-)rarr3I_(2)+3H_(2)O+CI^(-))/((a) "The stoichiometry of" HSO_(4)^(-) is 6` The `H^(+) "ions are provided by" H_(2)SO_(4) "or" HsO_(4)^(-)` ion (b) `I^(-)` ions are oxidisded to `I_(2)` (d) `H_(2)O` is one of the products formed in the redox rection. |
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