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For the reaction in equilibrium: 2NOBr_((g)) hArr 2NO_((g)) + Br_(2(g)) If P_(Br_(2)) is (P)/(9)t equilibrium and P is totalpressure, If (P)/(Kp) = x^(2) then what is x value. |
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Answer» <BR> Solution :`2NOBr_((g)) harr 2NO_((g))+Br_(2)`pressure at equilibrium `P-(3P)/(9), (2P)/(9), (P)/(9)` `P_(T)=(6P)/(9)+(2P)/(9)+(P)/(9)=P` `K_(P)=(P^(2)NO.PBr_(2))/(P^(2)NOBR)=(((2p)/(9))^(2) xx P)/(((6P)/(9))^(2)) IMPLIES K_(P)=(P)/(81)` Given `(P)/(K_(P))=x^(2), K_(P)=(P)/(x^(2))=(P)/(81) implies x=9` |
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