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For the reaction `M^(x+)+MnO_(4)^(ө)rarrMO_(3)^(ө)+Mn^(2+)+(1//2)O_(2)` if `1 "mol of" MnO_(4)^(ө)` oxidises `1.67 "mol of" M^(x+) "to" MO_(3)^(ө)`, then the value of `x` in the reaction isA. `5`B. `3`C. `2`D. `1` |
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Answer» Correct Answer - C `5e^(-)+MnO_(4)^(ө)rarrMn^(2+)` `M^(x+)rarrMO_(3)^(ө)+(5-x)` `x-6 = -1` `x=5` `"Equivalent of" MnO_(4)^(ө) = "Equivalent of" M^(x+)` `1 mol xx 5= 1.67 mol xx (5-x)` `:. X=2` |
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