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InterviewSolution
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For the reaction `M^(x+)+MnO_(4)^(ө)rarrMO_(3)^(ө)+Mn^(2+)+(1//2)O_(2)` if `1 "mol of" MnO_(4)^(ө)` oxidises `1.67 "mol of" M^(x+) "to" MO_(3)^(ө)`, then the value of `x` in the reaction is |
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Answer» Correct Answer - 2 `Mn^(7+) + 5e rarr Mn^(2+)` `:. 1` mole of `MnO_(4)^(-)` accepts `5` moles of electrons. `:. 5` mole of electron are lost by `1.67` mole of `M^(x+)` `:. 1` mole of `M^(x+)` will lose electron `= (5)/(165) ~~ 3` moles Since `M^(x+)` change to `MO_(3)^(-)` (oxidation no. of `M = +5`) by accepting `3` electron `:. x = +5 - 3=+2` |
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