For the reaction, M^(x+) + MnO_(4)^(-)rarrMO_(3)^(-)+ Mn^(2+) + 1//2 O_2if one mole of MnO_4^(-)oxidises 1.67 moles of M^(x+) " to " MO_(3)^(-)then the value of x in the reaction is?

For the reaction, M^(x+) + MnO_(4)^(-)rarrMO_(3)^(-)+ Mn^(2+) + 1//2 O

1.	For the reaction, M^(x+) + MnO_(4)^(-)rarrMO_(3)^(-)+ Mn^(2+) + 1//2 O_2if one mole of MnO_4^(-)oxidises 1.67 moles of M^(x+) " to " MO_(3)^(-)then the value of x in the reaction is?
Answer» Solution :`overset(+7) (MnO_4^(-))+5e^(-) rarrMn^(2+)` Since 1 mole of `MnO_(4)^(-)`ACCEPTS 5 MOLES of electrons , therefore , 5 moles electrons are lost by 1.67moles of `M^(x+)` `:. 1`Mole of `M^(x+)` will lose electrons = 5/1.67 = 3 moles ( approx.) Since `M^(x+)`changes to `MO_(3)^(-)`( where O.N.of M = +5) by accepting 3 electrons `:. x = +5-3 =+2` `:. Mn^(7+)+5e rarr Mn^(2+)`