For the reaction N_(2)+3H_(2)hArr2NH_(3) at 773K, the value of K_(p)=1.4xx10^(-15). Calculate K_(c) (Given R = 8.314 JK^(-1)mol^(-1)).

For the reaction N_(2)+3H_(2)hArr2NH_(3) at 773K, the value of K_(p)=1

1.	For the reaction N_(2)+3H_(2)hArr2NH_(3) at 773K, the value of K_(p)=1.4xx10^(-15). Calculate K_(c) (Given R = 8.314 JK^(-1)mol^(-1)).
Answer» Solution :`K_(p)=K_(c)(RT)^(DELTAN),Deltan=2-4=-2` `1.4xx10^(-15)=K_(c)(8.314xx773)^(-2)` `K_(c)=1.4xx10^(-15)xx(8.314xx773)^(2)=5.782xx10^(-8)`