For the reaction, N_(2) + 3H_(2) hArr2NH_(3) in a vessel, equal moles of N_(2) and H_(2) are mixed to attain equilibrium.

For the reaction, N_(2) + 3H_(2) hArr2NH_(3) in a vessel, equal moles

1.	For the reaction, N_(2) + 3H_(2) hArr2NH_(3) in a vessel, equal moles of N_(2) and H_(2) are mixed to attain equilibrium.
Answer» `[N_(2)]=[H_(2)]` `[N_(2)] gt [H_(2)]` `[N_(2)] lt [H_(2)]` `[H_(2)] gt [NH_(3)]` Solution :