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For the reaction, N_(2) + 3H_2 rarr2NH_(3)if E_1and E_2equivalent masses of NH_3 and N_2respectively then E_1 -E_2 is

Answer»

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Solution :`OVERSET(0)(N_2)RARROVERSET(-3)(2NH_3),overset(-3)(2NH_3)rarroverset(O)(N_2)`
`17/6-(28)/3,(34-28)/6=6/6 =1`


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