For the reaction : N_(2)(g)+3H_(2)(g)=2NH_(3)(g) Equilibrium constant K_(c)=([NH_(3)]^(2))/([N_(2)][H_(2)]^(3))

For the reaction : N_(2)(g)+3H_(2)(g)=2NH_(3)(g) Equilibrium constant

1.	For the reaction : N_(2)(g)+3H_(2)(g)=2NH_(3)(g) Equilibrium constant K_(c)=([NH_(3)]^(2))/([N_(2)][H_(2)]^(3))
Answer» SOLUTION :NA