1.

For the reaction N_(2) O_4 (g) hArr 2NO_(2) (g) K_(C)= 0.21 at 373 K . The concentration of N_(2) O_(4) and NO_(2) are found to be 0.125 mol dm^(-3) and 0.5 mol dm^(-3) respectively at a given temperature . Predict the direction of the reaction.

Answer»

At equilibrium
REVERSE DIRECTION
forward direction
Both reverse and forward direction

Solution :`Q = ([NO_(2)]^(2))/([N_(2) O_(4)]) = (0.5 xx 0.5)/(0.215) = 2`
`K_(C) = 0.21 , Q =2 `
`Q gt K_(C)`Hence the reaction will proceed in the reverse direction


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