For the reaction :N204 → 2 NO2(g) (g)∆H°= +57. 24 kJ, ∆S°=175.

1.	For the reaction :N204 → 2 NO2(g) (g)∆H°= +57. 24 kJ, ∆S°=175.8 Jk^-1At what temperature the reaction will be spontaneous?
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For the reaction :N204 → 2 NO2(g) (g)∆H°= +57. 24 kJ, ∆S°=175.8 Jk^-1At what temperature the reaction will be spontaneous?

Answer»

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