For the reaction :N204 → 2 NO2∆H°= +57.24kJ, ∆S°= 175.8 JK^-1

1.	For the reaction :N204 → 2 NO2∆H°= +57.24kJ, ∆S°= 175.8 JK^-1 at what temperature the reaction will be spontaneous
Answer» ANSWER: This is too HARD MAN just LEAVE it

For the reaction :N204 → 2 NO2∆H°= +57.24kJ, ∆S°= 175.8 JK^-1 at what temperature the reaction will be spontaneous

Answer»

This is too HARD MAN just LEAVE it