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For the reaction PCl_(3)(g) + Cl_(2)(g) rArr PCl_(5)(g) at 250^(@) C, then value of K_(c) is 26 then the value of K_(p)on the same temperature wil be ...........

Answer»


Solution :`Deltan_(G) = 1-2=-1`
`K_(p)-K_(c)(RT)^(Delta)ng= 26(0.0821 xx 523 )^(-1)` = 0.61


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