

InterviewSolution
Saved Bookmarks
1. |
For the reaction `PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g)` Which of the following sketches may represent above equilibrium? Assume equilibrium can be achieved from either side and by taking any one or more components initially. Give `K_(c )` for the reaction `lt 2`?A. B. C. D. |
Answer» Given: `K_(c)lt2` for `PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g)` a. From graph, find the vlue of `K_(c )` `K_(c )=(([PCl_(3)][Cl_(2)])/([PCl_(5)]))_(Eq)=(4xx6)/2 gt 2` (a) is incorrect. b. Incorrect: Since the concentration of both `PCl_(5)(g)` and `Cl_(2)(g)` will either increase or decrease, here it is increasing for `Cl_(2)(g)` and decreasing for `PCl_(3)(g)`. c. Note that (from graph) the initial concentration of `PCl_(5)` is zero. So the equilibrium is established as follows: `PCl_(3)(g)+Cl_(2)(g)hArrPCl_(5)(g)` From graph, `x=6`. Also note that (from graph), `b lt 6` (i.e., initial concentration of `Cl_(2))`, which means that `xlt 6`. It is not so, hence choice (c ) is incorrect. Obviously this should be the correct choice. However, let us check it. Find `K_(c )`. `K_(c )=(([PCl_(3)][Cl_(2)])/([PCl_(5)]))_(Eq)=(2xx4)/6 lt 2` `:. (d)` is correct. |
|