1.

For the reaction `PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g)` Which of the following sketches may represent above equilibrium? Assume equilibrium can be achieved from either side and by taking any one or more components initially. Give `K_(c )` for the reaction `lt 2`?A. B. C. D.

Answer» Given:
`K_(c)lt2` for `PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g)`
a. From graph, find the vlue of `K_(c )`
`K_(c )=(([PCl_(3)][Cl_(2)])/([PCl_(5)]))_(Eq)=(4xx6)/2 gt 2`
(a) is incorrect.
b. Incorrect: Since the concentration of both `PCl_(5)(g)` and `Cl_(2)(g)` will either increase or decrease, here it is increasing for `Cl_(2)(g)` and decreasing for `PCl_(3)(g)`.
c. Note that (from graph) the initial concentration of `PCl_(5)` is zero. So the equilibrium is established as follows:
`PCl_(3)(g)+Cl_(2)(g)hArrPCl_(5)(g)`

From graph, `x=6`. Also note that (from graph), `b lt 6` (i.e., initial concentration of `Cl_(2))`, which means that `xlt 6`. It is not so, hence choice (c ) is incorrect.
Obviously this should be the correct choice.
However, let us check it. Find `K_(c )`.
`K_(c )=(([PCl_(3)][Cl_(2)])/([PCl_(5)]))_(Eq)=(2xx4)/6 lt 2`
`:. (d)` is correct.


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