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For the reaction, `SnO_(2)(s)+2H_(2)(g) hArr Sn(l)+2H_(2)O(g)` the equilibrium mixture of steam and hydrogen contained `45%` and `24% H_(2)` at `900 K` and `1100 K` respectively. Calculate `K_(p)` at both the temperature. Generally should it be higher or lower temperatures for better reduction of `SnO_(2)`? |
Answer» Correct Answer - A::C::D `{:(,SnO_(2)(s),+,2H_(2)(g),hArr,Sn(l),+,2H_(2)O(g)),("Case I:",900 K,,,,45,,55):}` `:. K_(C_(1))=((55)^(2))/((45)^(2))=1.494` `{:(,SnO_(2)(s),+,2H_(2)(g),hArr,Sn(l),+,2H_(2)O(g)),("Case I:",1100 K,,24,,,,76):}` `:. K_(C_(2))=(76xx76)/(24xx24)=10.03` `K_(C)` increases with temperature and thus the reaction should be endothermic. Thus, high temperature is perferred for reduction of `SnO_(2)`. |
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