For the reaction : SrCO_3 (s) hArr SrO(s)+ CO_2(g), the value of equilibrium constnat K_P = 2.2 xx 10^(-4) " at " 1002 K. Calculate K_C for the reaction.

For the reaction : SrCO_3 (s) hArr SrO(s)+ CO_2(g), the value of equil

1.	For the reaction : SrCO_3 (s) hArr SrO(s)+ CO_2(g), the value of equilibrium constnat K_P = 2.2 xx 10^(-4) " at " 1002 K. Calculate K_C for the reaction.
Answer» Solution :For the REACTION, `SrCO_3(s) hArr SrO(s) + CO_2(g)` `Deltan_g = 1- 0 =1` `:. K_P = K_C (RT)` `2.2 XX 10^(-4) = K_C (0.082)(1002)` `K_C = (2.2 xx 10^(-4))/(0.0821 xx 1002) = 2.674 xx 10^(-6)`