For the reaction, SrCO_(3(s)) hArr SrO_((s)) + CO_(2(g)) , the value of equilibrium constant K_P = 2.2xx10^(-4)at 1002 K . Calculate K_C for the reaction ?

For the reaction, SrCO_(3(s)) hArr SrO_((s)) + CO_(2(g)) , the value o

1.	For the reaction, SrCO_(3(s)) hArr SrO_((s)) + CO_(2(g)) , the value of equilibrium constant K_P = 2.2xx10^(-4)at 1002 K . Calculate K_C for the reaction ?
Answer» SOLUTION :For the REACTION , `SrCO_3(s) hArr SrO(s) + CO_2(g)` `Deltan_g = 1-0 = 1 ` `thereforeK_p = K_C =(RT)` `2.2xx10^(-4) = K_C (0.0821) (1002) ` `K_C =(2.2xx10^(-4))/(0.0821xx1002) =2.674xx10^(-6)`