1.

For the reaction X_(2)O_(4)(l) rarr 2XO_(2)(g), DeltaU = 2.1 kcal , DeltaS =20 calK^(-1) at300K.Hence,DeltaGis

Answer»

2.7 kcal
`-2.7 kcal`
9.3 kcal
`-9.3kcal`

Solution :`DeltaH=DeltaU+Deltan_(G) RT`
Given`:DeltaU =2.1 kcal ,Deltan_(f) = 2-0=2`,
`R = 2 xx 10^(-3) kcal, T= 300K`
`:. DeltaH =2.1+ 2 xx 2XX 10^(-3) xx 300 = 3.3 kcal`
Again, `DeltaG= DeltaH - T DELTAS`
Given `: DeltaS =20 xx 10^(-3) kcal K^(-1)`
`DeltaH= 3.3 kcal` ( calculateabove)
`:. DeltaG = 3.3 - 300 xx (20 xx 10^(-3))`
`=3.3-6 = - 2.7 kcal`


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