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For the reaction X_(2)O_(4)(l) rarr 2XO_(2)(g), DeltaU = 2.1 kcal , DeltaS =20 calK^(-1) at300K.Hence,DeltaGis |
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Answer» 2.7 kcal Given`:DeltaU =2.1 kcal ,Deltan_(f) = 2-0=2`, `R = 2 xx 10^(-3) kcal, T= 300K` `:. DeltaH =2.1+ 2 xx 2XX 10^(-3) xx 300 = 3.3 kcal` Again, `DeltaG= DeltaH - T DELTAS` Given `: DeltaS =20 xx 10^(-3) kcal K^(-1)` `DeltaH= 3.3 kcal` ( calculateabove) `:. DeltaG = 3.3 - 300 xx (20 xx 10^(-3))` `=3.3-6 = - 2.7 kcal` |
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