For the reaction, X_(2)O_(4)(l) to 2XO_(2)(g) DeltaU = 2.1 kcal, DeltaS=20 cal K^(-1) at 300 K hence, DeltaG is

For the reaction, X_(2)O_(4)(l) to 2XO_(2)(g) DeltaU = 2.1 kcal, Delta

1.	For the reaction, X_(2)O_(4)(l) to 2XO_(2)(g) DeltaU = 2.1 kcal, DeltaS=20 cal K^(-1) at 300 K hence, DeltaG is
Answer» `2.7` kcal `-2.7` kcal `9.3`kcal `-9.3` kcal Solution :`X_(2)O_(4)(l) to 2XO_(2)(g)` `DeltaH = 2.1 kcal = 2100 cal, DeltaS = 20 cla K^(-1)` `DeltaH = DELTAU + Deltan_(g) RT` `Deltan_(g) = 2-0 = 2 ,R = 2 cal K^(-1) mol^(-1), T = 300 K` `DeltaH = 2100 + (2 xx 2 xx 300) = 3300 cal` `DeltaG = DeltaH-TDeltaS` = `3300 - 300(20) = -2700 cal = -2.7 kcal`