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For the redox reaction: `Cr_(2)O_(7)^(2-)+H^(o+)+NirarrCr^(3+)+Ni^(2)+H_(2)O` The correct coefficient of the reactants for the balanced reaction are:A. `Cr_(2)O_(7)^(2-)=1, Ni=3, H^(o+)=14`B. `Cr_(2)O_(7)^(2-)=3, Ni=3, H^(o+)=12`C. `Cr_(2)O_(7)^(2-)=2, Ni=3, H^(o+)=14`D. `Cr_(2)O_(7)^(2-)=1, Ni=1, H^(o+)=16` |
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Answer» Correct Answer - A `14H^(o+)+cancel(6e^(-))+Cr_(2)O_(7)^(2-)rarr2Cr^(3+)+7H_(2)O` `2x=14=-2, 2x=6` `2x=12` `NirarrNi^(+2)+cancel(2e^(-))]xx3` `ulbar(14H^(o+)+CrO_(7)^(2-)+3Ni2Cr^(3+)+3Ni^(2+)+7H_(2)O)` |
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