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For the redox reaction `MnO_(4)^(-)+C_(2)O_(4)^(-2)+H^(+) rarr Mn^(2+)+CO_(2)+H_(2)O` the correct coefficients of the reactants for the balanced reaction areA. `{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+)),(2,5,16):}`B. `{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+)),(16,5,2):}`C. `{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+)),(5,16,2):}`D. `{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+)),(2,16,5):}` |
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Answer» Correct Answer - A `MnO_(4)^(-) + 8H^(+) + 5e^(-) rarr Mn^(2+) + 4H_(2) O xx 2` `(c_(2)O_(4)^(2-) rarr 2 CO_(2) + 2e^(-) xx 5)/(2MnO_(4)^(-) + 5C_(2)O_(4)^(2-) + 16H^(+) rarr 2Mn^(2+) + 10CO_(2) + 8H_(2)O)` Thus the coefficient of `MnO_(4)^(-), C_(2)O_(4)^(2-) and H^(+)` in the abovve balanced equation respectively are 2, 5, 16 |
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