1.

For the redox reaction MnO_(4)^(-)+C_(2)O_(4)^(2-)+H^(+)toMn^(2+)+CO_(2)+H_(2)O the correct coefficients of the reactants for the balanced equation are

Answer»

`{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+)),("5","16","2"):}`
`{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+)),("16","5","2"):}`
`{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+)),("2","16","5"):}`
`{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+)),("2","5","16"):}`

Solution :
n = 5 of `MnO_(4)^(-)`, n = 2 of `C_(2)O_(4)^(-2)`, Ration = 5 : 2
So, Balanced equation :
`2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+)to2Mn^(2+)+10CO_(2)+8H_(2)O`


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