InterviewSolution
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InterviewSolution
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For the reduction of `NO_(3)^(c-)` ion in an aqueous solution, `E^(c-)` is `+0.96V`, the values of `E^(c-)` for some metal ions are given below `:` `i.V^(2+)(aq)+2e^(-)rarr V, " "E^(c-)=-1.19V` `ii. Fe^(3+)(aq)+3e^(-) rarr Fe, " "E^(c-)=-0.04V` `iii. Au^(3+)(aq)+3e^(-) rarr Au, " "E^(c-)=+140V` `iv. Hg^(2+)(aq)+2e^(-) rarr Hg, " "E^(c-)=+0.86V` The pair`(s)` of metals that is `//` are oxidized by `NO_(3)^(c-)` in aqueous solution is `//` areA. `Fe` and `Au`B. `Hg` and `Fe`C. `V` and `Hg`D. `Fe` and `V` |
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Answer» Correct Answer - b,c,d `NO_(3)^(c-)+e^(-) rarr ?, E^(c-)._(red)=0.96V` Compare the standard reduction potential of the given metals with that of `NO_(3)^(c-)` reduction. `E^(c-)._(reduction)` for `NO_(3)^(c-)` is greater than `E^(c-)._(reduction)` of `(i),(ii),` and `(iv).` So, `NO_(3)^(c-)` will be able to oxidize `Fe, Hg` and `V.` So pairs are as in `(b),(c),` and `(d)`. |
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