For the reversible reaction, N_(2) (g) + 3 H_(2) (g) hArr 2 SO_(3) (g) The equilibrium shifts in the forward direction

For the reversible reaction, N_(2) (g) + 3 H_(2) (g) hArr 2 SO_(3) (g)

1.	For the reversible reaction, N_(2) (g) + 3 H_(2) (g) hArr 2 SO_(3) (g) The equilibrium shifts in the forward direction
Answer» by increasing the CONCENTRATION of `NH_(3)` by decreasing the pressure by decreasing the pressure by decreasing the concentration of `N_(2) (g) and H_(2)` (g) Solution :As forward reaction is accompanied by decrease in the number of moles, applying Le Chatelie'rs principle , increses of pressure will shift the equilibrium in the forward DIRECTION, Also , as forward reaction is exothermic , increases of TEMPERATURE will shift the equilibrium in the forward direction .